
Kenneth S. answered 07/14/16
Tutor
4.8
(62)
Algebra II EXPERT will help you survive & prosper
P = k•I2•R from 1st sentence.
100 = k(52)(4) tells us, after substituting the givens, k = 1.
Now P = IR and you're going to substitute I = 8 amperes, R = 11 ohms, thus giving the P, in watts for the situation given in the second part of the 2nd sentence.