what numbers are divisible by 5, 10 and 2?

Question

Which numbers are divisible by 5, 10, and 2?

Answer 1

Common multiples of 2, 5, and 10 are divisible by 2, 5, and 10.

Answer 2

To find the smallest number divisible by 5, 10, and 2:

 

Factor the 3 numbers:

5 = 5

10 = 2*5

2 = 2

 

Multiply the common factors times the uncommon factors.  In this case, there are no common factors, and there are uncommon factors of 2 and 5.

 

The minimum common multiple is then 2*5 = 10.

 

That is the smallest number divisible by 5, 10, and 2.

 

Answer 3

The decimal number system is a positional number system.  That means that each digit represents a multiple of 10.  So, we have ones place, tens place, hundreds place, thousands place ... and we have tenths place and hundredths place, etc.

 

Any integer that is a multiple of 10 is also a multiple of 5 and a multiple of 2 -- that's because 10=5*2.

 

So, when you write any integer, if it ends with a "0" (like, for example, 30), then it is evenly divisible by 5, 10, and 2.

 

Also note, if the integer does not end with a "0" in ones place, then it is not divisible by all three (5, 10, and 2), but it may still be divisible by either 2 (like, for example, 28) or 5 (like, for example, 25).