Exponential functions. Solving for x

Question

Hi, I need help solving this : 

 

(1/e)^-x = (1/e²)^x+1 

Answer 1

(1/e)^-x = (1/e²)^x+1

e^x = (e^-2)^x+1

e^x = e^-2x-1

x = -2x - 1

3x = -1

x = -1/3