Hi Jessica,
Since the distance is equal to the rate times the time, the first part of the trip can be described as 250 = rt and the second part of the trip is
112 = (r+6)(7-t). Solve the first equation for either of the variables lets say t. Then t = 250/r. Substituting this value of t into the second equation produces 112 = (r+6)(7-250/r). Use the distributive property on the right side gives us 112 = 7r - 250 + 42 - 1500/r. Combine like terms and multiply both sides by r to get
112r = 7r2 - 208r - 1500 Rewrite the equation in standard form as 0 = 7r2 - 320r - 1500 Use the quadratic formula to get the value of r to be 50 or -30/7. Since it makes no sense to have a negative time, ignore the negative solution and use r = 50 for the first part of the trip and 56 for the second part of the trip.