
Mark M. answered 07/07/16
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Mathematics Teacher - NCLB Highly Qualified
(a)
The end of the parade and the runner are 1 mile apart.
2(t) + 6(t) = 1
8t = 1
t = 0.125
(b)
The front of the parade has a 1 mile head start.
parade: d = 2(t)
runner: d + 1 = 6t
2t = 6t - 1
-4t = -1
t = 0.25

Mark M.
You are welcome. Glad to have helped!
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07/07/16
Jane J.
07/07/16