Darryl K. answered 07/06/16
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Let x represent mL of 6% solution and y represent mL of 11% soltion
I will list the steps first. If you get stuck scroll on down to see the solution.
1) Write an equation that relates x, y and 350
2) The amount of vinegar in solution 1 + the amount of vinegar in solution 2 = the amount of vinegar in the final solution. To find the amount of vinegar in a solution multiply the percentage time the number of mL of that solution.
Write an equation that relates 0.06, x, 0.11, y, 0.07 and 350
3) Solve the two equations
Solution.
eq1) x+y=350
eq2) 0.06x+0.11y=0.07(350) simplifying 0.06x+0.11y=24.5 multiply each term by 100 gives 6x+11y=2450
Solve the first equation for either x or y and substitute into the second equation.
x=350-y
6(350-y)+11y=2450
2100-6y+11y=2450
5y=350
y=350/5=70
x=350-70=280
Use 70mL of the 11% solution and 280mL of the 6% solution