
Mariann B.
asked 06/30/16I need the equation for an algebraic answer
X6 _ y6
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2 Answers By Expert Tutors

Degonimia H. answered 07/01/16
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1 Assignments
2 Homework
3 Online courses
4 Online Exams
5 Classroom exams
In subjects
1 Finance
2 Statistics
3 Economics
4 Accounting
5 Operations Research
6 Econometric
7 Investments
8 Mathematics
9 Physics
10 Chemistry
11 Probability
12 Business
13 Project Management
14 C programming
15 C++ Programming
Work related to
Minitab
Excel
SPSS
R language
If you have work related to other subjects, I have a bunch of tutors for other subjects at very low prices.
If you wish for live tutoring. I have a separate platform for that at rate 10 dollars per hour.
Perks
1 you can pay me after getting your work done.
2 My fees will be very less as compared to Wyzant and other tutoring sites.
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Wei-Chyung Wang
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Alan G. answered 06/30/16
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Mariann,
Do you need to factor this polynomial? Here is how to do it.
You can recognize this as a difference of squares or a difference of cubes:
x6 − y6 = (x2)3 − (y2)3 or (x3)2 − (y3)2.
I will show you how to do this both ways, because it is interesting.
Here are the formulas for factoring you will need:
a3 − b3 = (a − b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 − ab + b2)
a2 − b2 = (a − b)(a + b)
x6 − y6 = (x2)3 − (y2)3 = (x2 − y2)(x4 + x2y2 + y4) = (x − y)(x + y)(x4 + x2y2 + y4)
and
x6 − y6 = (x3)2 − (y3)2 = (x3 − y3)(x3 + y3) = (x − y)(x2 + xy + y2)(x + y)(x2 - xy + y2).
These answers are both correct, but the second one is completely factored, while the first one is not. If you compare the two, you can notice that
x4 + x2y2 + y4 = (x2 + xy + y2)(x2 - xy + y2).
This is extremely hard to factor by yourself, so the best way to approach a problem like this one is to factor the original polynomial as a difference of squares. This is one of those questions where there are two ways of looking at it, but one of them wins out as getting the answer with less pain and suffering, and we all want that.
I hope this helps you, although it is quite a lot of explanation. Feel free to post a reply if you need more help with it.
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Mark M.
06/30/16