Tom F.

asked • 06/27/16

find the root soultion of y=2x^2+5x+9

  =2x^2+5x+9

2 Answers By Expert Tutors

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Degonimia H. answered • 07/01/16

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Efficient work at reduced prices

JOHN F. answered • 06/27/16

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Getting you that job or raise by augmenting your skillset

Andrew M.

Looking at the original equation:
y = 2x^2 + 5x+ 9
and looking for the roots, giving:
2x^2 + 5x + 9 = 0
We know this graphs as a parabola opening upward since
the coefficient of the square term is positive.  Thus, the
minimum output value will be at the vertex of the parabola.
 
This gives us a way to quickly determine if there will be real roots or not.
 
Given a quadratic of the form ax^2 + bx + c = 0
the x coordinate of the vertex is at x=-b/2a
 
a = 2
 
 
Report

06/28/16

Andrew M.

Sorry, computer bump... lol
 
For 2x^2 +5x +9 = 0
a = 2,  b=5,  c = 9
 
-b/2a = -5/2 = -2.5
 
The y value at that point is:
2(2.5)^2 + 5(2.5) + 9 = 34
 
The vertex of the paraboloa is at (-2.5, 34) and it opens upward.
Thus, it will never touch the x axis, meaning there are no real roots.
Which tells us that the roots will be complex.
 
****************************************
Just food for thought for the future.  The vertex of a parabola is at
(-b/2a, f(-b/2a))
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06/28/16

Andrew M.

Wow.  Now I look like an idiot.  x = -2.5, not 2.5 at the vertex so 
y = 2(-2.5)^2 + 5(-2.5) + 9 = 9
 
The vertex is at (-2.5, 9) and opens upwards....
 
I'll stop now..   lol
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06/28/16

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