Physics getting the force

Question

A 2m crowbar is employed to lift a 200 kg load. What force must a man apply to one end of the crowbar when a stone (acting as a fulcrum) is placed under the crowbar 20 cm away from the end on which the object rests? Disregard the weight of the crowbar.

Answer 1

The pivot point is 0.2 m from the 200 kg load, and (2 - 0.2)m = 1.8 m from the end where we apply the force.  Just do equilibrium of moments.  Note this problem is simple because we are told to neglect the weight of the crowbar. 

 

(200 kg)(9.8 m/s²)(0.2 m) = F (1.8 m)

 

F = (200)(9.8)(0.2) / 1.8 N = 217.8 N

Answer 2

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