This is the concept of composite functions.There are two functions here: F and G.
For F+G, you focus on adding the second (y) coordinates of both function that correspond to the same element in the domain (x).
F+G = {(1, 2+4), (3, (5+0)} = {(1,6), (3,5)}
F/G = {(1, 2/4), (3, 5/0)} = {(1,0.5), (3, undefined)}. This means that, the function F/G is not defined at x = 3, that is, there is a vertical asymptote at x = 3.
You may ask why points corresponding to x =4 and x = 5 are not included. This is because they are not included simultaneously in F and G above. There is no information on (5,?) in F, and none on (4,?) in G. However, if these two functions were plotted, it may be possible to get this information from each graph. Actually, F+G is a summation of two functions. F/G is the division of function F by function G.
I hope this suffices. If you need more help, let me know by contacting wyzant.


MICHAEL E.
tutor
Thank you for your observation.
Irrespective of whether it is a discrete function or not, it is obvious that the function F/G is not defined at x = 3. Off
course, if it is not defined at x = 3, then F/G is not a continuous function.
In addition, if you enter these coordinates into Microsoft Excel, you will find that a line of best fit can be drawn. In fact, if you do this, you find functions F and G to be quadratic with the correlation coefficient approximately 1 and R^2 (coefficient of determination) to be 1. Therefore, a mere inspection of coordinates may not easily determine the type of function. However, more points need to be given for a conclusive determination. Please, try to input these coordinates into Excel separately for F and G. You can also use algebraic method, that is using the typical vertex form of a quadratic function, a(x-h)^2 + K.
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06/19/16
Kenneth S.
06/19/16