This is a geometric sequence. The formula is l=a(r)^(n-1) where l is the last term, a is the first term,
r is the common ratio, and n is the number of terms.
{3, -12, 48, -192, ...}
To find any term use 3[(-4)^(n-1)]
The first term is 3[(-4)^(1-1)]=3(-4)^0=3(1)=3
The second term is 3[(-4)^(2-1)]=3[(-4)^1]=3(-4)=-12
The third term is 3[(-4)^(3-1)]=3[(-4)^2]=3(16)=48
The fourth term is 3[(-4)^(4-1)]=3[(-4)^3]=3[-64)=-192
The fifth term is 3[(-4)^(5-1)]=3[(-4)^4]=3(256)=768
Looking at the sequence, multiply any term by -4 to
get the next term in the sequence.
