Richard C. answered 06/12/16
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Jessica,
You didn't indicate what the confidence level in the test is (α). Assuming α = .05, then looking for the critical value of t with n = 12 in a t-table, we find that:
tcritical = 2.179
So, since 2.08 < 2.179, we cannot reject the null hypothesis that the means are equal.
Should note that tcritical is dependent on α and n.
Hope this helps!