Arturo O. answered 06/11/16
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The amount obeys an exponential decay law:
N(t) = N(0)e-kt
Given a half-life T = 5730 years,
e-kT = 1/2
k = - ln(1/2) / T = - ln(1/2) / 5730 = 1.209681 x 10-4 years-1
Since the amount present dropped to 50% (i.e. 1/2 of the initial amount), then one half-life has elapsed, so the age is 5730 years.
Mark M.
06/11/16