Dan D. answered 06/10/16
Tutor
4.9
(434)
Patient Tutor Focused on Your Understanding of Math
Emily,
Here is the answer to a similar problem:
https://www.wyzant.com/resources/answers/223137/my_question_is_in_the_description
For your problem we have p=q=1/2,
and you want the case for n=5 which is given by:
1 = (p+q)5 = 1p5 + 5p4q + 10p3q2 + 10p2q3 + 5pq4 + 1q5
Because p=q=1/2, the pq parts of all of these terms are all the same: (1/2)5 = 1/32, so we have:
1 = (1 + 5 + 10 + 10 + 5 + 1) /32
The 6 different terms give the probabilites for 5 heads, 4 heads, ..., one head, zero heads.
In a table:
heads Probability
0 1/32
1 5/32
2 10/32
3 10/32
4 5/32
5 1/32
0 1/32
1 5/32
2 10/32
3 10/32
4 5/32
5 1/32
You can use a calculator to do the divisions and round each of them to 5 decimal places.