Arturo O. answered 06/09/16
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I assume you want to solve
A^2 - 5A - 6I = 0 (the matrix 0)
If you try factoring this like it was just numbers, you get
(A + 1I)(A - 6I) = (A + I)(A - 6I) = A^2 - 6AI + IA - 6I^2
Recall AI = IA = A and I^2 = I
Then
(A + 1I)(A - 6I) = A^2 - 6A + A - 6I = A^2 - 5A - 6I
So this appears to be a valid factorization.
Then A = -I and A = 6I are solutions.