
Arturo O. answered 05/27/16
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c = speed of light
v = speed of object
L0 = length of object when at rest
L = length of object when moving at speed v
According to special relativity,
L = L0 * sqrt[1 - (v/c)^2]
L < L0, so tho faster object will appear shorter than the slower object, i.e. the slower object will appear longer than the faster object, which is answer (D)