number of coach tickets, number of sleeper car tickets

Question

Ninety one passengers rode in a train from City A to City B. Tickets for regular coach seats cost ?$113 . Tickets for sleeper cars seats cost ?$290 . The receipts for the trip totaled ?$19,664 . How many passengers purchased each type of? ticket?

Answer 1

Jessica, here we go...

 

r + s = 91

113r + 290s = 19664

 

We need to "solve" the first equation for either r or s. Let's do r.

 

r = 91 - s

 

Now, we substitute this "value" for r into the 2nd equation.

 

113(91 - s) + 290s = 19664

10283 - 113s + 290s = 19664

177s = 9381

s = 53

 

r = 91 - 53 = 38

 

Hope this helps!