F(x)=2(x-2)^2-2

Question

Identity the vertex, y-intercept, zeros, axis of symmetry, and intervals of increase & decrease.

Answer 1

When a quadratic function has the form

 

f(x) = a(x - h)² + k,

 

the vertex is (h,k). You can find the y-intercept by setting x = 0, the axis of symmetry will be x = h, and the value of a determines whether the graph (parabola) opens upward (a > 0) or downward (a < 0). Once you know this, the last question is easily answered.

 

To start, what are a, h, and k for this equation?