Solve for x and check any extraneous roots : root 5x-1=1 root x+2

Question

Solve for x and check any extraneous roots : root 5x-1=1 root x+2

Answer 1

√(5x - 1) = 1

[√(5x - 1)]² = 1²

5x - 1 = 1 

5x = 2

x = 2/5

 

Let's check solution in the original equation

√(5 * 2/5 - 1) = 1
√(2 - 1) = 1
√1 = 1
  1 = 1

Thus, x = 2/5 is not an extraneous root.