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Solve for x and check any extraneous roots : root 5x-1=1 root x+2

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1 Answer

√(5x - 1) = 1

[√(5x - 1)]2 = 12

5x - 1 = 1 

5x = 2

x = 2/5
 
Let's check solution in the original equation

√(5 * 2/5 - 1) = 1
√(2 - 1) = 1
√1 = 1
  1 = 1

Thus, x = 2/5 is not an extraneous root.

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