Help!!!!! please!

Question

How much heat does it take to raise the temperature of 3.5 kg of water from 25C to 46C? The specific heat of water is 4.18 kJ/(kg C).
Use Q = mc(Tf - Ti).
A. 310 kJ

B. 88 kJ

C. 74 kJ

D. 160 kJ

Answer 1

This is just direct substitution:

 

m = 3.5

c = 4.18

Ti = 25

Tf = 46

 

Using the formula:

 

Q = mc(Tf-Ti)

Q = 3.5*4.18*(46-25)

 

Q = 307.23 kJ ≈ 310 kJ