Kylie H.

asked • 05/07/16

What is his acceleration down the hill?

Duane has a mass of 73 kg and slides down an icy hill on a sled. The hill has an angle of 15 degrees and there is no friction. 
 
I know that acceleration is the change in velocity/ time but it doesn't seem that I have enough information...

1 Expert Answer

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Stephen R. answered • 05/08/16

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Kylie H.

Thank you! That makes sense. The next question is wanting me to account for friction now. The coefficient of kinetic friction between him and the hill is 0.15. How do I put that in the equation? 
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05/09/16

Stephen R.

To show the effect of friction on the motion you need to calculate force.
The force due to gravity is mass dependent and is equal to:
Fg = m ag                        where Fg = force due to gravuty, m = mass of object, and ag = acceleration due to gravity.
Fg = (73 kg)(2.5 m/s^2)        substituting the value obtained above for the acceleration.
Fg = 182.5 kg.m/s^2 or 183 N
 
Ff = uN                           where Ff = force due to friction, u = coefficient of kinetic friction, and N is the normal force.
Ff = (0.15)(183 N)           coefficient of friction is dimensionless and acts in the opposite direction of the applied force.
Ff = 27.4 N
Net Force = Fg - Ff 
Net Force = 183 - 27.4
Net Force = 155.6 N
 
 
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05/09/16

Kylie H.

Thank you very much! It all makes sense now :)
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05/09/16

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