x = rcosθ
y = rsinθ
x2+y2 = r2
Since r = 4cosθ, r2 = 4rcosθ
x2+y2 = 4x
x2-4x+y2 = 0
Complete the square: (x2-4x+4) + y2 = 4
(x-2)2 + (y-0)2 = 4
This is a circle with center (2,0) and radius 2.