Consider the quadratic equation x^2=4x-5. How many solutions does the equation have?

Question

A)The equation has 1 real solution.

B)The equation has 2 real solutions.

C)The equation has no real solutions.

D)The number of solutions cannot be determined.

 

I need some help here.

Answer 1

x² = 4x - 5

x² - 4x = -5        subtract 4x from both sides

x² - 4x + 5 = 0  add 5 to both sides

 

What is the value of the discriminant?