It's an algebra problem

-3√(5x

^{3}) . √(10x^{3})^{ }=-3√(5x

^{3})^{ }. √(2.5x^{3})^{ }=-3 . √(5x

^{3}) . √(2) . √(5x^{3}) =-3 . √(2) . 5x

^{3}=-15x

^{3}√(2)-
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It's an algebra problem

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-3√(5x^{3}) . √(10x^{3})^{ }=

-3√(5x^{3})^{ }. √(2.5x^{3})^{ }=

-3 . √(5x^{3}) . √(2) . √(5x^{3}) =

-3 . √(2) . 5x^{3} =

-15x^{3}√(2)

Hi Chris;

-3v5x^3 x v10x^3

The coefficients of v are -3 and 1...(-3)(1)=-3

(v)(v)=v^{2}

The coefficients of x are (5) and (10)...(5)(10)=50

(x^{3})(x^{3})=x^{6}...because exponents 3+3=6

-3v^{2}50x^{6}

-3 √(5X^3) * √(10X^3) =

-3 √(50 X^6) = - 15 X^3 √2

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