Roman C. answered 04/25/16
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Recall that (n-1)s2/σ2 ~ χ2 with n-1 degrees of freedom. This actually calls for a left-tailed test, since HA states that σ < 35.
The test statistic is
χ2 = 10·322/352 = 8.359...
Using the χ2 table with df = 10 shows that the p-value is between 0.1 and 0.9 (this range may differ depending on the percentiles listed in the table in your book).
Or you can use software (e.g. in R, calling pchisq(8.359,df=10) ) to get that the p-value is 0.4061854...
Thus we can't reject H0 and the claim is not believable.