Find the first six terms of the sequence defined recursively by a1=2, a2=3 and an+1=an-an-1

Question

Find the first six terms of the sequence defined recursively by a₁=2, a₂=3 and a_n+1=a_n-a_n-1

Answer 1

Greetings! Lets solve this shall we ?

So, we must find the first six terms where the first two terms are a₁ = 2 and a₂ = 3 and a_n+1 = a_n - a_n-1. Then, we find the next four terms such that to find the next term, plug in the number 3, 4 and so forth to get

a₃ = a₂ - a₁ = 3 - 2 = 1

a₄ = a₃ - a₂ = 1 - 3 = -2

a₅ = a₄ - a₃ = -2 -1 = -3

a₆ = a₅ - a₄ = -3 - (-2) = -1

I hope this helped!