Exponential Equation: 3^(x-1)=17
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(x+1) log(3) = log(17) ... A TYPO... SHOULD BE (x-1)
x+1 = log(17) / log (3) ... A TYPO... SHOULD BE (x-1)
Forgive us tutors, we sometimes make accidental typing errors.
MATH (preCalculus, Calculus, Algebra, Geometry) Physics
Initially, you have to eliminate the exponent by taking the log of BOTH sides of the equation.
the problem then becomes
log10(3(x-1)) = log1017
That then becomes
(x+1) log(3) = log(17) ...
x+1 = log(17) / log (3)
The rest should be easy
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