log base m (1/m)

Question

(hint: m is positive number)

Answer 1

log_m(1 / m)

 

 

Realizing that this is a quotient/subtraction rule for logs,

 

log_m(1) - log_m(m)

 

 

For the first term, m raised to the what power results in 1?  That power is 0.

For the second term, m raised to what power results in m?  That power is 1.

 

log_m(1) - log_m(m) =

 

0 - 1 =

 

-1

Answer 2

log(m)(1/m)

log(m)(m^-1)

-1log(m)(m)

log(m)(m)=1

-1(1)

-1