Doug C. answered 13d
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Let's try:
y = sin[tan(x2 - 3)]2
y' = 2[sin(tan(x2 - 3))]1 • cos[tan(x2 - 3)] • sec2(x2 - 3) • 2x
= 4x • sin[tan(x2 - 3)] • cos[tan(x2 - 3)] • sec2(x2 - 3)
The chain rule was used 3 times.
- Derivative of sin[tan(x2 - 3)] = cos[tan(x2 - 3)]
- Derivative of tan(x2 - 3) = sec2(x2 - 3)
- Derivative of x2 - 3 = 2x