
Arturo O. answered 05/30/16
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The solution to the differential equation is
T(t) = A + (T0 - A)*e^(-kt)
T0 = initial temperature of body
We need a value for k.
T goes from 100 deg to 90 deg in 1 minute.
A = 70 deg, T0 = 100 deg, T(1 min) = 90 deg
90 = 70 + (100 - 70)*e^[-k(1)]
k = - ln(20/30) = 0.405465 deg/min
T(4 min) = 70 + (100 - 70)*e^[-(0.405465)(4)]
T(4 min) = 75.93 degrees C, i.e. about 76 degrees C