
Mark M. answered 04/12/16
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Mathematics Teacher - NCLB Highly Qualified
A = a0(0.5)t/h
0.886a0 = a0(0.5)t/5550 substitution
0.886 = (0.5)t/5550 divide both sides by a0
ln 0.886 = ln (0.5)t/5550
-0.1210 ≈ (t/5550)(-0.6931)
-671.76 ≈ -0.6931t
721.55 ≈ t
The approximate date of the settlement was 1965 - 721.55, or 1243.