Roman C. answered 04/12/16
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For |x| ≤ π/2 we have: cos-1 sin x = π/2 - x
This follows from the identity sin x = cos(π/2 - x) and the range [0,π] of the function cos-1 x.
cos-1 sin π/3 = π/2 - π/3 = π/6