Write an equation for a line perpendicular to y = - 5 x + 2 y=-5x+2 and passing through the point (15,7)

Question

Write an equation for a line perpendicular to
y
=
−
5
x
+
2
y=-5x+2 and passing through the point (15,7)

Answer 1

The perpendicular line *always* has a slope of the negative reciprocal. Your given line has a slope of -5, so the perpendicular slope is -1/(-5) = 1/5.

 

Use the point-slope form of a general line to find the equation.

 

(y - y_1) = m * (x - x_1)

 

y - 7 = (1/5) * (x - 15)

 

I hope this helps!