Arthur D. answered 04/08/16
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(30-2w)(40-2w)=(1/2)(30)(40)
1200-80w-60w+4w^2=600
4w^2-140w+1200-600=0
4w^2-140w+600=0
w^2-35w+150=0
150=2*3*5*5=30*5 and 30+5=35
factor
(w-30)(w-5)=0
w-30=0
w=30 (don't use this number because you will get negative dimensions)
w-5=0
w=5 feet is the width of the walkway
(30-10)(40-10)=20*30=600 which is half of 30*40 which is 1200