Inactive Tutor answered 11/24/12
Draw free body diagram first. Using Newton's second law ,
T - 5g(0.162) = 5a ......(1)
9g - T = 9a ......(2)
(1)/(2): [T - 5g(0.162)]/[9g - T] = 5/9
Solve for T,
T = 36.60 N
Taliyah H.
asked 11/24/12A 9.00 kg hanging weight is connected by a string over a pulley to a 5.00 kg block that is sliding on a flat table (Fig. P5.49). If the coefficient of kinetic friction is 0.162, find the tension in the string.
Image Link ( http://www.webassign.net/sb5/p5-49.gif )
Inactive Tutor answered 11/24/12
Draw free body diagram first. Using Newton's second law ,
T - 5g(0.162) = 5a ......(1)
9g - T = 9a ......(2)
(1)/(2): [T - 5g(0.162)]/[9g - T] = 5/9
Solve for T,
T = 36.60 N
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Taliyah H.
Thank youu
11/24/12