Equation of circle given center and tangent line
Write the equation for a circle which has its center at (1, 2) and is tangent to the line -3x+2y= 14 Solve algebraically.
I know that the equation of a circle is r2=(x-h)2+(y-k)2. So, at this point the equation is r2=(x-1)2+(y-2)2. I also can rearrange the tangent line equation to get y=(3/2)x+7. I was wondering if I can just substitute (3/2)x+7 for y in the equation of the circle. If I can't, what should I do? If I can, is there a better way to do this? Thanks.