Evaluate problem

Question

Given that the antiderivative of f(x)= 1/x is F(x) =Ln|x|+ C,  

 

             ²

evaluate ∫ 1/x dx
              ¹
ln3
1/2
-1/2

1n2

 

Answer 1

Jesse

 

As you noted the antiderivative or integral of 1/x is ln |x| + C

So

 

 ∫₁² 1/x dx

ln |x| |²₁  = ln|2| - ln|1| = .693 - 0 = .693

 

Editing to add the answer per the choices above is ln 2 (remember ln 1 = 0)