What is the equation of a line with slope 3/4 and passing through (-1, -6). Write it in slope-intercept form.?

Question

I am having problems on how to write this out and doing it can someone please help me math is not my strong point, thank you

Answer 1

You should recognize that you have been given a slope and an ordered pair which is a point consisting of an x and y coordinate.  You can use the Point-Slope equation for a linear line very easily by just plugging in these values.  y - (-6) = 3/4(x - (-1).  The next step is you need to solve for y.  Solving for y will put this in the desired slope-intercept form of a linear equation y = mx + b.  Remember you end up working with fractions so make sure you add/subtract after finding a common denominator.  The solution is y = (3/4)x - 21/4.

Answer 2

The equation is going to be of the form y=(3/4)x+something.  It passes through (-1,-6)

In order to walk to the y-axis from (-1,-6) you need to walk 1 step positive in x, from -1 to 0.

In order to stay on the line you must then walk up 3/4 step in y to -5 1/4=-21/4

y=(3/4)x-21/4

 

Answer 3

First we have the point slope formula:

y-y₁=m(x-x₁)     ................ equation1

 

Here in the given question, y₁=-6 ,x₁=-1

Plugging these values in equation 1

[y-(-6)]=3/4[x-(-1)]

y+6=3/4(x+1)

y+6=3/4x+3/4

y=3/4x-21/4