First, draw the region.
A typical cross section has diameter e-x
Volume of semicircular cross section = (1/2) π(e-x/2)2dx
= π(e-2x/8)dx
Volume of solid = π∫(from 0 to 1)(e-2x/8)dx
= -π/16(e-2x) (from 0 to 1)
= -π/16(e-2 - 1)
= π/16(1 - 1/e2)
≈ 0.17