Mark M. answered 03/09/16
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Use the trig substitution x = secθ
Then the integral becomes
∫(from π/4 to π/3)(secθtanθdθ)/[secθ√tan2θ]
= ∫(from π/4 to π/3) dθ = θ(from π/4 to π/3) = π/3 - π/4 = π/12