how do you solve 2sqrt3/6 by hand?

Question

I have two Quantities A and B.

Quantity A is 2 radical 3 over 6

Quantity B is 1 over radical 3

using a graphing or scientific calculator I can solve this but I don't know how to do this by hand.

 

 

Please help

Answer 1

A = (2√3)/6 = √3/3

 

B = 1/√3 

 

Multiply B by 1 in the form of √3/√3 to get B = (1/√3)*(√3/√3) = √3/√9 = √3/3 

 

Since A and B are equal to the same value they are equal to each other 

 

P.S.  The technique for B is called rationalizing the denominator