Marlene S. answered 03/08/16
Tutor
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(2,813)
Retired Actuary with 20+ years of Calculus Tutoring Experience
Hi Morgan
We have been given
f(t) = at2 - bt + 20
and the first derivative is
f'(t) 2at-b
We also have f'(1) = 10 and f'(15) = 80
So evaluate the first derivative at each value of t
f'(1) = 2a-b = 10
f'(15) = 30a-b = 80
Subtract f'(1) from f'(15)
28a = 70
a = 5/2
Then use this value of a in one of the f'(t) equations and solve for b.
f'(1) = 2(5/2) - b = 10
5-b = 10
b=-5
a = 5/2
b = -5
Morgan D.
03/20/16