Equate 0.5mv2 to mgh and obtain v2/2 = gh or v is (2gh)0.5.
An iron block of 10 kilograms released 10 meters above the ground on Earth
increases in velocity by 9.80665 meters per second every second that it
remains in free fall.
Just before release, the block's Gravitational Potential Energy or GPE is given by
10 kg x 9.80665 m/s2 x 10 m which goes to 980.665 kg•m2/s2 or 980.665 Joules
(where 1 Joule is a Force of 1 Newton driving through a Distance of 1 Meter).
Just before ground impact the block's Kinetic or Mechanical Energy is given by
0.5mv2 or 0.5 x 10 kg x (2 x 9.80665 m/s2 x10 m)(0.5 x 2) or 980.665 kg•m2/s2
or 980.665 Joules which matches GPE found above. The Velocity sought just
before ground impact is (2gh)0.5 or 14.00474919 meters per second.