Janelle S. answered 03/02/16
Tutor
4.7
(26)
Penn State Grad for ME, Math & Test Prep Tutoring (10+ yrs experience)
If N(0) is the initial amount of iodine 131, t is the elapsed time, t1/2 is the half life of iodine 131, and N(t) is the amount of iodine 131 left after the elapsed time, you get the equation for exponential decay:
N(t) = N(0) * (1/2)^[t/(t1/2)] = 0.001mol * (1/2)^[8days / 8days] = 0.001mol * (1/2)^1 = 0.001mol * 1/2 = 0.0005mol
(This checks out since half of the sample would decay during one half life)
Amount of iodine 131 that decayed = N(0) - N(t) = 0.001mol - 0.0005mol = 0.0005mol
Set up proportion to see how many moles of beta rays are emitted:
1mol beta ray x mol beta rays
________________ = ___________________
1mol iodine 131 0.0005mol iodine 131
x mol beta rays * 1mol iodine 131 = 1mol beta ray * 0.0005mol iodine 131
x mol beta rays = (1mol * 0.0005mol) / 1mol = 0.0005 mol beta rays
Set up another proportion with Avogadro's number to find the number of beta rays emitted:
Avogadro's number = 6.02 x 10^23 molecules / mol
6.02 x 10^23 beta rays x beta rays
_______________________ = _____________
1mol 0.0005mol
x beta rays * 1mol = 6.02x10^23 beta rays * 0.0005mol
x beta rays = (6.02x10^23 beta rays * 0.0005mol) / 1mol = 3.01 x 10^20 beta rays

Janelle S.
tutor
No problem Alex! Let me know if you need help with anything else.
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03/02/16
Alex C.
03/02/16