solvefor x. please help

Adding to Shefali's answer:

There is one missing detail here. It's true that x = -1 is the only candidate for the solution and would have multiplicity 2, however, you must plug it into the original equation to see if it works. It turns out that it doesn't because x+1=0 is raised to the negative power and 0^{p} is undefined when p < 0.

Indeed, the graph of y = 1/3(x + 1)^{-2/3} has a point-discontinuity at the point (-1,0).