A charge of 5.7 µC produces an electric field.

Question

a) Does the electric field point toward or away from the charge? Explain.

 

b) What is the magnitude of the electric field 0.45 m from the charge?

Answer 1

Since the charge is positive, then the electric field is pointing AWAY rom it.

at 0.45 m, E = kQ/r^2 = 9x10^9(5.7x10^-6)/0.45^2 = 253333 N/C