Equate (Power Rating Of Kettle) Times (t Seconds) To
(Specific Heat For Water) Times (Mass Of Water) Times (Change In Temperature).
Build the equation as 1500 (Watts Or Joules/Second) x t (Seconds) Equals
4184 (Joules Per Kilogram Per Degree Celsius) x (1 Kilogram) x [(88 - 18) (Degrees Celsius)].
Rewrite as 1500t J = 4184 (J/Kg/°C) x 1 (Kg) x 70 (°C), which reduces to t = 195.2533333 Seconds.
195.2533333 Seconds Divided By 3.6 Minutes (or 216 Seconds) gives (195.2533333/216) or
0.9039506171 equivalent to 90.4% efficiency for the kettle.