Twice the sum of a number and 9 is equal to three times the difference of a number and 5

Question

Twice the sum of a number and 9 is equal to three times the difference of a number and 5

Answer 1

Let's represent the number as n.

First, write out the expression in algebraic form: 2(n+9)=3(n-5)

Next, simplify the algebraic expression by distributing the 2 and 3: 2n+18=3n-15

Next, simplify the expression further by putting like terms on each side: 18+15=3n-2n becomes 33=n

So, n=33

Answer 2

First, write put the information into an equation

 

2*(x+9) = 3*(x-5)

 

distribute the 2 and 3

2x + 18 = 3x - 15

 

Combine like terms (Xs and munbers) (in this case, it's easier to add 15 to both sides and subtract 2x from both sides so both sides end up being positive)

33 = x

 

x=33

Answer 3

The number is 33.

Suppose the number is X.

2(X+9)=3(X-5)

So, X=33