Quadratics Formula

Question

How do you solve this equation using the quadratic formula?

 

2x^2+2x+5=0

Answer 1

a=2

b=2

c=5

 

(-b+- (_{b^2-4ac)^(1/2))/2a}

(-2+-(4-40)^(1/2))/4

(-2+-SQRT(-36))/4

(-2+-6i)/4

-2(1-+3i)/4

(-1+-3i)/2

or

(-1+3i)/2 and (-1-3i)/2 are the two solutions using the quad formula