F(x)=(6x+5)/(x^2-5x+4) domain?

Question

domain? 

Answer 1

Hi Court,

 

f(x)=(6x+5)/(x² -5x+4),

You want to find the points where the denominator vanishes, those points are not included in the domain because the f(x) does not exist at those points.

x² -5x +4 = 

(x -4)(x - 1) = 0

x-4 = 0 or x - 1 = 0

x = 4, x =1

The domain of  f(x) is (-∞, 1)U(1, 4)U(4, ∞)